Relative Frequency

POINT
Relative frequency = frequency of the class ÷ total frequency. The relative frequencies add up to 1.
EXAMPLE
Find A, B and C in the frequency table.
Class intervalFrequencyRelative frequency
0–1060.15
10–208B
20–30AC
30–40120.30
40–5040.10
Total401.00
A = 40 − (6 + 8 + 12 + 4) = 10
B = 8 ÷ 40 = 0.20
C = 10 ÷ 40 = 0.25

Practice

Complete the frequency and relative frequency table.

01
Class intervalFrequencyRelative frequency
0–1050.17
10–207?
20–30??
30–4060.20
40–5030.10
Total301.00
Frequency (20–30) = 9
Relative frequency (10–20) = 7 ÷ 30 = 0.23
Relative frequency (20–30) = 9 ÷ 30 = 0.30
02
Class intervalFrequencyRelative frequency
0–104?
10–20100.25
20–3080.20
30–40??
40–5060.15
Total401.00
Frequency (30–40) = 12
Relative frequency (0–10) = 4 ÷ 40 = 0.10
Relative frequency (30–40) = 12 ÷ 40 = 0.30
03
Class intervalFrequencyRelative frequency
0–1080.27
10–20??
20–3070.23
30–4040.13
40–506?
Total301.00
Frequency (10–20) = 5
Relative frequency (10–20) = 5 ÷ 30 = 0.17
Relative frequency (40–50) = 6 ÷ 30 = 0.20
04
Class intervalFrequencyRelative frequency
0–1060.15
10–2090.23
20–305?
30–4080.20
40–50??
Total401.00
Frequency (40–50) = 12
Relative frequency (20–30) = 5 ÷ 40 = 0.125
Relative frequency (40–50) = 12 ÷ 40 = 0.30
05
Class intervalFrequencyRelative frequency
0–10??
10–2060.15
20–30110.28
30–407?
40–50130.33
Total401.00
Frequency (0–10) = 3
Relative frequency (0–10) = 3 ÷ 40 = 0.075
Relative frequency (30–40) = 7 ÷ 40 = 0.175
← Previous lessonNext lesson →